y^2=280

Solution for y^2=280 equation:

y^2=280

We move all terms to the left:

y^2-(280)=0

a = 1; b = 0; c = -280;
Δ = b2-4ac
Δ = 02-4·1·(-280)
Δ = 1120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1120}=\sqrt{16*70}=\sqrt{16}*\sqrt{70}=4\sqrt{70}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{70}}{2*1}=\frac{0-4\sqrt{70}}{2}
=-\frac{4\sqrt{70}}{2}
=-2\sqrt{70}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{70}}{2*1}=\frac{0+4\sqrt{70}}{2}
=\frac{4\sqrt{70}}{2}
=2\sqrt{70}
$